x^2+44x-5600=0

Solution for x^2+44x-5600=0 equation:

x^2+44x-5600=0

a = 1; b = 44; c = -5600;
Δ = b2-4ac
Δ = 442-4·1·(-5600)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-156}{2*1}=\frac{-200}{2}
=-100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+156}{2*1}=\frac{112}{2}
=56
$